Let \(V(G) = \{v_1, v_2, \ldots, v_n\}\) be the vertex set of \(G\) and let \(d_{G}(v_i)\) be the degree of a vertex \(v_i\) in \(G\). The degree subtraction adjacency matrix of \(G\) is a square matrix \(DSA(G)=[d_{ij}]\), in which \(d_{ij}=d_{G}(v_i)-d_{G}(v_j)\), if \(v_i\) is adjacent to \(v_j\) and \(d_{ij}=0\), otherwise. In this paper we express the eigenvalues of the degree subtraction adjacency matrix of subdivision graph, semitotal point graph, semitotal line graph and total graph of a regular graph in terms of the adjacency eigenvalues of \(G\). Further we obtain the degree subtraction adjacency energy of these graphs.
Let \(G\) be a simple, undirected graph with vertex set \(V(G) = \{v_1, v_2, \ldots, v_n\}\) and edge set \(E(G) = \{e_1, e_2, \ldots, e_m\}\). The degree of a vertex \(v_i\) denoted by \(d_{G}(v_i)\) is the number of edges incident to it. If all vertices have same degree equal to \(r\) then \(G\) is called an \(r\)-regular graph.
The adjacency matrix of \(G\) is a square matrix of order \(n\), defined as \(A=A(G)=[a_{ij}]\), where \(a_{ij}=1\) if \(v_i\) is adjacent to \(v_j\) and \(a_{ij}=0\), otherwise. The characteristic polynomial of \(A(G)\) is denoted by \(\phi(G:\lambda)\), that is, \(\phi(G:\lambda)= \det|\lambda I-A(G)|\), where \(I\) is an identity matrix. The characteristic polynomial of the adjacency matrix of a complete graph \(K_n\) is \(\phi(K_n : \lambda) = (\lambda – n + 1)(\lambda + 1)^{n-1}\). The roots of the equation \(\phi(G:\lambda)=0\) are called the adjacency eigenvalues of \(G\) [1] and they are denoted by \(\lambda_{1}, \lambda_{2}, \ldots, \lambda_{n}\). Two non-isomorphic graphs are said to be cospectral if they have same eigenvalues. For any graph \(G\), \(-\Delta\leq \lambda_{i} \leq \Delta\), where \(\Delta\) is the maximum degree. Thus for an \(r\)-regular graph, \(\lambda_{i}+ r\geq 0\) for \(i= 1, 2, \ldots, n\).
The vertex-edge incidence matrix of \(G\) is defined as \(B=B(G)=[b_{ij}]\), where \(b_{ij}=1\) if the vertex \(v_i\) is incident to an edge \(e_j\) and \(b_{ij}=0\), otherwise.
It is easy to observe that [1] $$BB^T=A+D,$$ where \(D= \text{diag} [d_G(v_1), d_G(v_2), \ldots, d_G(v_n)]\) is a diagonal degree matrix of \(G\) and \(B^T\) is the transpose of \(B\). If \(G\) is an \(r\)-regular graph, thenLemma 2.1. If \(M\) is a non-singular matrix, then we have \[ \left| \begin{array}{cc} M & N \\ P & Q \end{array}\right| = |M||Q-PM^{-1}N|. \]
Theorem 2.2. Let \(G\) be an \(r\)-regular graph on \(n\) vertices and \(m\) edges. Then \[ \psi(S(G):\xi) = \left\{\begin{array}{ll} \xi^{\frac{n}{2}}(\xi^2+2)^{\frac{n}{2}}, & \mathrm{if} \hspace{4mm} r= 1 \\[2mm] \xi^{2n}, & \mathrm{if} \hspace{4mm} r = 2\\[2mm] (-1)^{n} (r-2)^{2n} \xi^{m-n} \phi\left(G: \frac{-\xi^2-r(r-2)^{2}}{(r-2)^2}\right), & \mathrm{if} \hspace{4mm} r \geq 3. \end{array} \right. \]
Proof. (i) If \(r=1\), then \(G\) is a union of \(k \geq 1\) edges. Thus \(G\) has \(n=2k\) vertices and \(k\) edges. The vertices of \(S(G)\) can be labeled in such a way that \[ DSA(S(G)) = \left[ \begin{array}{cc} O & B^T \\ -B & O \end{array}\right], \] where \(B\) is vertex-edge incidence matrix of \(G\) and \(O\) is zero matrix. Therefore by Lemma 2.1 and Eq.(1) \begin{eqnarray*} \psi(S(G) : \xi) & = & \left|\begin{array}{cc}\xi I_m & – B^T \\ B & \xi I_n \\ \end{array}\right|\\ & = & \xi^m \left|\xi I_{n} + B \frac{I_{m}}{\xi} B^T \right| \\ & = & \xi^{m-n} \left|\xi^2 I_{n} + BB^T \right| \\ & = & \xi^{m-n} \left|\xi^2 I_{n} + A + rI_{n}\right| \\ & = & (-1)^n\xi^{m-n} \left|-(\xi^2 + r)I_{n} – A \right| \\ & = & (-1)^n\xi^{m-n} \phi(G: -(\xi^2 + r)) \\ & = & (-1)^{2k}\xi^{k-2k} \left((\xi^2+1)^2-1 \right)^{k}\\ & = & \xi^{k} (\xi^2+2)^{k} \\ & = & \xi^\frac{n}{2}(\xi^2+2)^\frac{n}{2}. \end{eqnarray*}
(ii) If \(r=2\), then each component of \(G\) is cycle. Therefore \(S(G)\) is \(2\)-regular graph on \(2n\) vertices. Hence \[ \psi(S(G):\xi)= \xi^{2n}. \]
(iii) Let \(r\geq 3\). The vertices of \(S(G)\) can be labeled in such a way that \[ DSA(S(G)) = \left[ \begin{array}{cc} O & (2-r) B^T \\ -(2-r)B & O \end{array}\right], \] where \(B\) is vertex-edge incidence matrix of \(G\) and \(O\) is zero matrix. Therefore by Lemma 2.1 and Eq.(1) \begin{eqnarray*} \psi(S(G) : \xi) & = & \left|\begin{array}{cc}\xi I_m & – (2-r)B^T \\ (2-r)B & \xi I_n \\ \end{array}\right|\\ & = & \xi^m \left|\xi I_{n} + (2-r)^2 B\frac{I_{m}}{\xi} B^T \right| \\ \nonumber & = & \xi^{m-n} \left|\xi^2 I_{n} + (r-2)^2(A+rI) \right| \\ & = & (-1)^n(r-2)^{2n}\xi^{m-n} \left|\left(\frac{-\xi^2-r(r-2)^2}{(r-2)^2}\right)I_n – A \right| \\ & = & (-1)^n(r-2)^{2n}\xi^{m-n} \phi\left(G: \frac{-\xi^2- r(r-2)^2}{(r-2)^2}\right). \end{eqnarray*}
By Theorem 2.2, we have following corollary.Corollary 2.3. Let \(G\) be an \(r\)-regular graph on \(n\) vertices and \(m\) edges. Let \(\lambda_1, \lambda_2, \ldots, \lambda_n\) be the adjacency eigenvalues of \(G\) and \(\mathbf{i}=\sqrt{-1}\).
(i) If \(r=1\) then DSA-eigenvalues of \(S(G)\) are \(0\) (\(\frac{n}{2}\) times) and \(\pm \mathbf{i}\sqrt{2}\) (\(\frac{n}{2}\) times).
(ii) If \(r=2\) then DSA-eigenvalues of \(S(G)\) are all zeros.
(iii) If \(r\geq 3\) then DSA-eigenvalues of \(S(G)\) are \(0\) (\(m-n\) times) and \(\pm \mathbf{i}(r-2)\sqrt{r+\lambda_i}\), \(i=1, 2, \ldots, n\).
The semitotal pont graph of \(G\), denoted by \(T_{1}(G)\), is a graph with vertex set \(V(G)\cup E(G)\) and two vertices in \(T_{1}(G)\) are adjacent if they are adjacent vertices in \(G\) or one is a vertex and other is an edge incident to it in \(G\) [19]. Note that if \(u\in V(G)\) then \(d_{T_{1}(G)}(u)= 2 d_{G}(u)\) and if \(e\in E(G)\) then \(d_{T_{1}(G)}(e)= 2\).Theorem 2.4. Let \(G\) be an \(r\)-regular graph on \(n\) vertices and \(m\) edges. Then \[ \psi(T_{1}(G):\xi) = \left\{\begin{array}{ll} \xi^{m+n}, & \mathrm{if} \hspace{4mm} r = 1\\[2mm] (-1)^n (2r-2)^{2n}\xi^{m-n} \phi\left(G: \frac{-\xi^2- r(2r-2)^2}{(2r-2)^2}\right), & \mathrm{if} \hspace{4mm} r\geq 2. \end{array} \right. \]
Proof. (i) If \(r=1\), then \(T_{1}(G)\) is a regular graph of degree two on \(m+n\) vertices. Hence \[ \psi(T_{1}(G):\xi) = \xi^{m+n}. \]
(ii) Let \(r \geq 2\). The vertices of \(T_1(G)\) can be labeled in such a way that \[ DSA(T_1(G)) = \left[\begin{array}{cc} O & (2-2r) B^T \\ -(2-2r)B & O \end{array}\right], \] where \(B\) is vertex-edge incidence matrix of \(G\) and \(O\) is a zero matrix. Therefore by Lemma 2.1, and Eq. (1) \begin{eqnarray*} \psi(T_1(G) : \xi) & = & \left|\begin{array}{cc}\xi I_m & – (2-2r)B^T \\ (2-2r)B & \xi I_n \\ \end{array}\right|\\ & = & \xi^m \left|\xi I_{n} + (2r-2)^2 B\frac{I_{m}}{\xi} B^T \right| \\ \nonumber & = & \xi^{m-n} \left|\xi^2 I_{n} + (2r-2)^2(A+rI) \right| \\ & = & (-1)^n(2r-2)^{2n}\xi^{m-n} \left|\left(\frac{-\xi^2-r(2r-2)^2}{(2r-2)^2}\right)I_n – A \right| \\ & = & (-1)^n(2r-2)^{2n}\xi^{m-n} \phi\left(G: \frac{-\xi^2- r(2r-2)^2}{(2r-2)^2} \right). \end{eqnarray*}
By Theorem 2.4, we have following corollary.corollary 2.5. Let \(G\) be an \(r\)-regular graph on \(n\) vertices and \(m\) edges. Let \(\lambda_1, \lambda_2, \ldots, \lambda_n\) be the adjacency eigenvalues of \(G\) and \(\mathbf{i}=\sqrt{-1}\).
(i) If \(r=1\) then DSA-eigenvalues of \(T_1(G)\) are all zeros.
(ii) If \(r\geq 2\) then DSA-eigenvalues of \(T_1(G)\) are \(0\) (\(m-n\) times) and \(\pm \mathbf{i}(2r-2)\sqrt{r+\lambda_i}\), \(i=1, 2, \ldots, n\).
Semitotal line graph of \(G\), denoted by \(T_2(G)\), is a graph with vertex set \(V(G)\cup E(G)\) and two vertices in \(T_2(G)\) are adjacent if one is a vertex and other is an edge incident to it in \(G\) or both are edges adjacent in \(G\) [1]. Note that if \(u\in V(G)\) then \(d_{T_2(G)}(u)= d_{G}(u)\) and if \(e= uv \in E(G)\) then \(d_{T_2(G)}(e)= d_{G}(u)+d_{G}(v)\).Theorem 2.6. Let \(G\) be an \(r\)-regular graph \((r\geq 1)\) on \(n\) vertices and \(m\) edges. Then \[ \psi(T_2(G) : \xi) = (-1)^n r^{2n}\xi^{m-n} \phi\left(G: \frac{-\xi^2- r^3}{r^2} \right). \]
Proof. The vertices of \(T_2(G)\) can be labeled in such a way that \[ DSA(T_2(G)) = \left[ \begin{array}{cc} O & r B^T \\ – rB & O \end{array}\right], \] where \(B\) is vertex-edge incidence matrix of \(G\) and \(O\) is a zero matrix. Therefore by Lemma 2.1 and Eq. (1) \begin{eqnarray*} \psi(T_2(G) : \xi) & = & \left|\begin{array}{cc}\xi I_m & – rB^T \\ rB & \xi I_n \\ \end{array}\right|\\ & = & \xi^m \left|\xi I_{n} + r^2 B\frac{I_{m}}{\xi} B^T \right| \\ \nonumber & = & \xi^{m-n} \left|\xi^2 I_{n} + r^2(A+rI) \right| \\ & = & (-1)^n r^{2n}\xi^{m-n}\left |\left(\frac{-\xi^2-r^3}{r^2}\right)I_n – A \right| \\ & = & (-1)^n r^{2n}\xi^{m-n} \phi\left(G: \frac{-\xi^2 – r^3}{r^2} \right). \end{eqnarray*}
By Theorem 2.6, we have following corollary.Corollary 2.7. Let \(G\) be an \(r\)-regular graph \((r\geq 1)\) on \(n\) verties and \(m\) edges. Let \(\lambda_1, \lambda_2, \ldots, \lambda_n\) be the adjacency eigenvalues of \(G\) and \(\mathbf{i}=\sqrt{-1}\). Then DSA-eigenvalues of \(T_2(G)\) are \(0\) (\(m-n\) times) and \(\pm \mathbf{i}r\sqrt{r+\lambda_{i}}\), \(i=1, 2, \ldots, n\).
Total graph of \(G\), denoted by \(T(G)\), is a graph with vertex set \(V(G)\cup E(G)\) and two vertices in \(T(G)\) are adjacent if and only if they are adjacent vertics of \(G\) or adjacent edges of \(G\) or one is a vertex and other is an edge incident to it in \(G\) [18]. Total graph of a regular graph is regular. Hence if \(G\) is regular, then \[ \psi(T(G): \xi) = \xi^{m+n}. \] Two different graphs having same eigenvalues are called cospectral. If \(G_1\) and \(G_2\) are adjacency cospectral graphs with same regularity, then by Corollaries 2.3, 2.5, and 2.7, the graphs \(S(G_1)\) and \(S(G_2)\); \(T_1(G_1)\) and \(T_1(G_2)\); \(T_2(G_1)\) and \(T_2(G_2)\) form a pair of DSA-cospectral graphs.Proposition 3.1. Let \(G\) be an \(r\)-regular graph on \(n\) vertices and \(m\) edges. Let \(\lambda_1, \lambda_2, \ldots, \lambda_n\) be the adjacency eigenvalues of \(G\). Then
(i) \[ DSAE(S(G)) = \left\{\begin{array}{ll} n\sqrt{2}, & \mathrm{if} \hspace{4mm} r= 1 \\[2mm] 0, & \mathrm{if} \hspace{4mm} r = 2\\[2mm] 2(r-2)\sum\limits_{i=1}^{n}\sqrt{r+\lambda_{i}}, & \mathrm{if} \hspace{4mm} r \geq 3. \end{array} \right. \]
(ii) \[ DSAE(T_1(G)) = \left\{\begin{array}{ll} 0, & \mathrm{if} \hspace{4mm} r= 1 \\[2mm] 2(2r-2)\sum\limits_{i=1}^{n}\sqrt{r+\lambda_{i}}, & \mathrm{if} \hspace{4mm} r \geq 2. \end{array} \right. \]
(iii) \(DSAE(T_2(G)) = 2r\sum\limits_{i=1}^{n}\sqrt{r+\lambda_{i}}\) for \(r \geq 1\).
(iv) \(DSAE(T(G))= 0\) for \(r\geq 1\).
By Proposition 3.1 we have following result.Proposition 3.2. If \(G\) is an \(r\)-regular graph \((r\geq 3)\) on \(n\) vertices, then
(i) \((2r-2) DSAE(S(G)) = (r-2) DSAE(T_1(G))\);
(ii) \(r DSAE(S(G)) = (r-2) DSAE(T_2(G))\);
(iii) \(r DSAE(T_1(G)) = (2r-2) DSAE(T_2(G))\).
Proposition 3.3. Let \(G\) be an \(r\)-regular graph \((r\geq 3)\) on \(n\) vertices. Then $$DSAE(S(G)) < DSAE(T_2(G)) < DSAE(T_1(G)).$$
Proof. For \(r\geq 3\), we see that $$r-2 < r < 2r-2.$$ Hence by Proposition 3.2, this implies $$DSAE(S(G)) < DSAE(T_2(G)) < DSAE(T_1(G)).$$