In this article, we revisit the axioms of JU-algebras previously recognizable as ‘pseudo KU-algebras’, which we may call as ‘weak KU-algebras’ and discussed the definitions of some of their substructures. We also associate this class of algebras with the classes of BE-algebras and UP-algebras. In addition, we introduce and analyze some new classes of ideals in this class of algebras.
Definition 1.[8] An algebra \((A, \cdot, 1)\) of type \((2, 0)\) with a binary operation ”\(\cdot\)” and a fixed element \(1\) is said to be JU-algebras satisfying the following axioms:
Lemma 1. [8] In the axioms system [JU], the following formulae are valid:
Comment 1. In [3], a KU-algebra is defined as a system \((A,\cdot,0)\) by the following axioms:
Comment 2. The concept of UP-algebras was introduced in 2017 in article [6] as a \((A,\cdot, 0) \) system that satisfies the following axioms:
Comment 3. The concept of BE-algebras is defined in [2] as a system \((A,\cdot,1)\) satisfying the following axioms:
Definition 2.[8] Let \(A\) be a JU-algebra. We define a relation ”\(\leqslant\)” in \(A\) as follows: $$\forall x, y \in A)(y \leqslant x \, \Longleftrightarrow \, x \cdot y = 1.$$
According to claims (J\(_{4}\)), (J\(_{5}\)), (J\(_{6}\)), and claims (J\(_{7}\)), (J\(_{8}\)), the relation “\(\leqslant\)” is a partial order in \( A \) left compatible and right reverse compatible with the internal operation in \(A\) [8].Proposition 1. Let \(A\) be a JU-algebra. Then
Proof.
Relation \((1)\) is obtained directly from (J\(_{12}\)) where, we put \(z = 1\).
If we put \( x = 1 \) and \(z = x\) in (JU-1), we get \((y \cdot x)\cdot ((x \cdot 1)\cdot (y \cdot 1)) = 1\). This means \(\varphi(x)\cdot \varphi(y) \leqslant y \cdot x\) according to the Definition 2.
If we put \(z = 1\) in (JU-1), we get \((y \cdot 1)\cdot((1 \cdot x)\cdot (y \cdot x)) = 1\). Hence \(\varphi(y)\cdot (x \cdot (y \cdot x)) = 1\). So, we have \(x \cdot (y \cdot x) \leqslant \varphi(y)\).
Relation \((4)\) is proved in [8] as formula (J\(_{14}\)).
Relation \((5)\) is a direct consequence of the right inverse compatibility of order relations with an internal operation in \( A \) if we choose \( z = 1 \).
Remark 1. The relation (5) of Proposition 1 is a direct consequence of the Proposition 1(4). Indeed, if \( x \leqslant y \), then \( y\cdot x = 1 \). Thus \(\varphi(y \cdot x) = 1\). Hence \(\varphi(y)\cdot \varphi(x) = 1\) by Proposition 1(4). This means \(\varphi(x) \leqslant \varphi(y)\).
Definition 3.[8] A non-empty subset \(J\) of a JU-algebra \(A\) is called a JU-ideal of \(A\) if
Lemma 2. Let \(J\) be a JU-ideal of a JU-algebra \(A\). Then
Proof. Let \(x, y \in A\) be such that \(x \leqslant y\) and \(y \in J\). Then \(y\cdot x = 1 \in J\) and \(y \in J\). Thus \(x \in J\) by (J-2).
Proposition 2. Let \(J\) be a subset of a JU-algebra such that (J-1) holds. Then the condition (J-2) is equivalent to the condition;
Proof. (J-4) \(\Longrightarrow\) (J-2). If we put \( x = 1 \), \( y = x \) and \( z = y \) in (J-4), then we get (J-2) with respect to (JU-2). (J-2) \(\Longrightarrow\) (J-4). Let \(x, y, z \in A\) such that \(x \cdots (y \cdot z) \in J\) and \(y \in J\). Then \(y \cdot (x \cdot z) \in J\) and \(y \in J\) by (J\(_{12}\)). Thus \(x \cdot z \in J\) by (J-2).
As a consequence of the Proposition 2, we can describe some of the features of the JU-ideals as follows:Proposition 3. Let \(J\) be a JU-ideal of a JU-algebra \(A\). Then
Proof. If we put \( z = y \) in (J-4), we get $$(x \cdot (y \cdot y) \in J \, \wedge \, y \in J) \Longrightarrow x \cdot y \in J.$$ From where, we get (J-5) using (J\(_{11}\)) in [8]. If we put \( z = 1 \) in (J-4), we get (7).
Definition 4. Let \(J\) be a JU-ideal of a JU-algebra \(A\), then
Theorem 1. An ideal \(J\) of a JU-algebra \(A\) is closed if and only if it is a subalgebra of \(A\).
Proof. Assume that an ideal \(J\) is a subalgebra of \(A\) and \(x \in J\). Then, from \(1 \in J\) and \(x \in J\) follows \(\varphi(x) = x \cdot 1 \in J\) because \(J\) is a subalgebra of \(A\). This means \(\varphi(J) \, \subseteq \, J\). Conversely, let an ideal \(J\) of \(A\) is closed and let \(x, y \in J.\) Then \(\varphi(x) \in \varphi(J) \, \subseteq \, J\) and \(y \in J\). Thus \(x \cdot y \in J\) by Proposition 3(6). This means that \(J\) is a subalgebra of \(A\).
As usual, we will write \(Ker\varphi = \{x \in A : \varphi(x) = 1 \}\). In [8], this set is labeled by \(B_{A}\).Corollary 1. \(Ker\varphi\) is a closed JU-ideal of \(A\).
Proof.
Let \(x, y \in A\) be such \(x \in Ker\varphi\) and \(x \cdot y \in Ker\varphi\). Then \(\varphi(x) = 1 \) and
\(1 = \varphi(x \cdot y) = \varphi(x) \cdot \varphi(y) = 1 \cdot \varphi(y) = \varphi(y)\) by Proposition 1(4) and (JU-2). Thus \(y \in Ker\varphi\). So, \(Ker\varphi\) is a JU-ideal of \(A\).
Suppose \(x \in Ker\varphi\) and \(y \in Ker\varphi\). Then, from \(\varphi(x) = 1\) and \(\varphi(y) = 1\) it follows \(\varphi(x \cdot y) = \varphi(x)\cdot \varphi(y) = 1 \cdot 1 = 1\) by Proposition 1(4). Thus \(x \cdot y \in Ker\varphi\).
So, \(Ker\varphi\) is a subalgebra in \(A\). Therefore \(Ker\varphi\) is a closed JU-ideal of \(A\) by Theorem 1.
Lemma 3. Let \(J\) be a JU-ideal of a JU-algebra \(A\), then
Proof. Let us first show that the following holds;
Definition 5. Let \(J\) be a JU-ideal of JU-algebra \(A\), then
Proposition 4. Let \(A\) be a JU-algebra, then
Proof. It has already been shown that \( \varphi^{2}(x) \leqslant x \) is valid. Thus \(\varphi(x) \leqslant \varphi^{3}(x)\) by Proposition 1(5) and \(\varphi^{3}(x)\cdot \varphi(x) = 1\). On the other hand, from \( 1 = \varphi^{2}(x) \cdot \varphi^{2}(x) = \varphi^{2}(x) \cdot \varphi(\varphi(x))\), it follows \( \varphi(x) \cdot \varphi^{3}(x) = 1\) according to Proposition 1(1). Thus \(\varphi^{3}(x) = \varphi(x)\) by (JU-3).
Corollary 2. \(Ker\varphi\) is a closed ag-ideal of \(A\).
Proof. It has already been shown that \( Ker\varphi \) is a closed JU-ideal of \( A \). Let \(x\in A\) be an arbitrary element such that \(\varphi^{2}(x) \in Ker\varphi\). Then \(\varphi(x) = \varphi^{3}(x) = 1\) by (9) given in proof of Lemma 3. Thus \(x \in Ker\varphi\).
Lemma 4. If \(J\) is a JU-ideal of a JU-algebra \(A\), then \(\varphi^{2}(J) = \{x \in A : \varphi^{2}(x) \in J\}\) is a JU-ideal of \(A\) also. The reverse also applies: If \(\varphi^{2}(J)\) is a JU-ideal of JU-algerba \( A \), then \( J \) is a JU-ideal of \( A \) also.
Proof.
Since \(1 \in J\), then \(\varphi^{2}(1) = 1 \in J\). Thus \(1 \in \varphi^{2}(J)\). Suppose \(x \in \varphi^{2}(J)\) and \(x \cdot y \in \varphi^{2}(J)\). Then \(\varphi^{2}(x) \in J\) and \(\varphi^{2}(x) \cdot \varphi^{2}(y) = \varphi^{2}(x \cdot y) \in J\) with respect to Proposition 1(4). Thus \(\varphi^{2}(y) \in J\) and \(y \in \varphi^{2}(J)\). So, \(\varphi^{2}(J)\) is a JU-ideal of JU-algebra \(A\).
It is obvious that \(1 = \varphi^{2}(1) \in J\) holds because \(1 \in \varphi^{2}(J)\) is valid. Let \(x, y \in A\) be such \(x \in J\) and \(x \cdot y \in J\). Then \(\varphi^{2}(x) \in \varphi^{2}(J)\) and
\(\varphi^{2}(x)\cdot \varphi^{y} = \varphi^{2}(x \cdot y) \in \varphi^{2}(J)\). Thus \(\varphi^{2}(y) \in \varphi^{2}(J)\) by (J-2) because \(\varphi^{2}(J)\) is a JU-ideal of \(A\). Hence \(y \in J\). Therefore, \(J\) is a JU-ideal of \(A\).
Theorem 2. \(J\) is a closed a JU-ideal of a JU-algerba \(A\) if and only if \(\varphi^{2}(J)\) is a closed JU-ideal of \(A\).
Proof. Let \(J\) be a closed a JU-ideal of a JU-algebra \(A\). Let \(x \in A\) be an element such that \(x\in \varphi(\varphi^{2}(J))\). Then \(\varphi(x) \in \varphi^{2}(J)\) and \(\varphi^{2} (\varphi(x)) = \varphi(\varphi^{2}x))\in J\). Thus \(\varphi^{2}(x) \in \varphi(J) \, \subseteq \, J\) because \(J\) is a closed ideal of \(A\). Hence \(x \in \varphi^{2} (J)\). From this it has shown that the ideal \(\varphi^{2}(J)\) satisfies Definition 4 condition (C). Let \(J\) be a JU-ideal of a JU-algebra \(A\) such that \(\varphi^{2}(J)\) is a closed JU-ideal of \(A\). Then, we have \[\varphi(J) = \varphi^{3}(J) = \varphi(\varphi^{2}(J)) \,\subseteq \, \varphi^{2}(J) \, \subseteq \, J\] by Proposition 4(10) and since the inclusion \(\varphi^{2}(J) \, \subseteq \, J\) is obviously valid. So, \(J\) is a closed JU-ideal of \(A\).
Before presenting the following theorem, we will introduce the concept of JU-filters in a JU-algebra.Definition 6. A subset \(F\) of a JU-algerba \(A\) is a JU-filter of \(A\) if the following hold:
Lemma 5. If \(F\) is a JU-filter of a JU-algerba \(A\), then
Proof. Let \(x, y \in A\) be such that \(x \in F\) and \(x \leqslant y\). Then \(x \in F\) and \(y \cdot x = 1 \in F\). Thus \(y \in F\) by (F-3).
Lemma 6. If \(F\) is a JU-filter of a JU-algebra \(A\), then
Proof. If we put \( y = 1 \) in (F-2), we immediately get (11).
Remark 2. In [8], the concept of strong JU-ideal of a JU-algebra was introduced in the way we introduced the concept of JU-filters.
Theorem 3. For a JU-ideal \(J\) of a JU-algerba \(A\) the following are equivalent:
Proof.
Definition 7. A subset \(J\) of a JU-algebra \(A\) is a t-ideal of \(A\) if the following hold:
Lemma 7. A t-ideal of a JU-algebra \(A\) is a JU-ideal of \(A\).
Proof. If we put \( x = 1 \), \( y = x \) and \( z = y \) in Dentition 7(t), we get condition (J-2).
In the following proposition we give some of the characteristics of this type of JU-ideals.Theorem 4. Let \(J\) be a t-ideal of a JU-algerba \(A\), then
Proof. If we put \( y = 1 \) in Definition 7(t), we get (e) with respect to (J-1). Let \(x, z \in A\) be such that \(\varphi(x) \cdot z \in J\). Then \[\varphi(\varphi^{2}(x))\cdot z = \varphi^{3}(x)\cdot z = \varphi(x)\cdot z \in J \,\Longrightarrow \, \varphi^{2}(x)\cdot z \in J\] by (e). To prove (g), we note that \((x \cdot 1)\cdot (x \cdot 1) = 1 \in J \) and \( 1 \in J\) follows \( x \cdot (x \cdot 1) \in J\) by Definition 7(t). So we have \(x \cdot \varphi(x) \in J\).
Proposition 5. The condition (e) of Theorem 4 is equivalent to the condition (t) of Definition 7.
Proof.
Theorem 4 already proves that (t) \(\Longrightarrow\) (e), the inverse implication (e) \(\Longrightarrow\) (t) remains to be proved.
We can write (JU-1) in the form \((y \cdot z) \cdot (y \cdot x) \leqslant z \cdot x\) according to (J\(_{12}\)). If we put \( z = 1 \), \( x = y \) and \( y = x \) in the previous inequality, we get
\(\varphi(x) \cdot (x \cdot y) \leqslant y\). From here, it follows \(\varphi(x) \cdot (x \cdot y) \in J\) by (J-3) and the hypothesis \(y \in J\).
On the other hand, if we put \( z = x \cdot y \), \( x = z \) and \( y = \varphi(x) \) in (JU-1) written in the form \((y \cdot z)\cdot (y \cdot x) \leqslant z \cdot x\), then we get
\((\varphi(x) \cdot (x \cdot y))\cdot (\varphi(x) \cdot z) \leqslant (x \cdot y) \cdot z\). Thus \((\varphi(x) \cdot (x \cdot y))\cdot (\varphi(x) \cdot z) \in J\) by (J-3) and the hypothesis \((x \cdot y) \cdot z \in J\).
Now, from \((\varphi(x) \cdot (x \cdot y))\cdot (\varphi(x) \cdot z) \in J\) and \(\varphi(x) \cdot (x \cdot y) \in J\) it follows \(\varphi(x) \cdot z \in J\). Thus \(x \cdot z \in J\) by (e).
Proposition 6. The condition (f) of Theorem 4 is equivalent to the condition (e) of Theorem 4.
Proof. Let \(x, z \in A\) be elements such that \(\varphi(x)\cdot z \in J\). Then \(\varphi^{2}(x) \cdot z \in J\) by (f). On the other hand, it follows \(x \cdot z \leqslant \varphi^{2}(x) \cdot z\) from (9) with respect to right reverse compatibility of the operation in \(A\) with the order in \(A\). Now, from \(x \cdot z \leqslant \varphi^{2}(x) \cdot z\) and \(\varphi^{2}(x) \cdot z \in J\) it follows \(x \cdot z \in J\) by (J-3).
This has shown that formula (e) is a consequence of formula (f).
As Theorem 4 already shows that (e) \(\Longrightarrow\) (f), we conclude that the condition (e) is equivalent to the condition (f).
Proposition 7. The condition (g) of Theorem 4 is equivalent to the condition (e) of Theorem 4.
Proof. Assume (g). Let \(x, y, z \in A\) be elements such that \(\varphi(x) \cdot z \in J\). If we put \( y = x \), \( x = z \) and \( z = \varphi(x) \) in (JU-1), written in the form \((z \cdot x) \cdot (t \cdot x) \leqslant y \cdot z\), we get
\((\varphi(x) \cdot z)\cdot (x \cdot z) \leqslant x \cdot \varphi(x)\). From here, it follows \((\varphi(x) \cdot z)\cdot (x \cdot z) \in J\) by (J-3) and the hypothesis (g): \(\varphi(x) \cdot x \in J\).
Now, from \((\varphi(x) \cdot z)\cdot (x \cdot z) \in J\) it follows \(x \cdot z \in J\) by (J-2) and hypothesis \(\varphi(x) \cdot z \in J\). We have shown by this that (g) \(\Longrightarrow\) (e).
In Theorem 4 it is shown that (t) \(\Longrightarrow\) (g). Since (t) \(\Longleftrightarrow\) (g) is a valid formula, by Proposition 5, we conclude that the equivalence of (e) \(\Longleftrightarrow\) (g) is a valid formula, too.
Definition 8.[8] A subset \(J\) of a JU-algebra \(A\) is called a p-ideal of \(A\) if
Lemma 8. Any p-ideal \( J \) of a JU-algebra \( A \) is a JU-ideal of \( A \).
Proof. If we put \( z = 1 \) in Definition 8(p), we get (JU-2).
Theorem 5. Let \(J\) be a p-ideal of a JU-algerba \(A\). Then
Proof.
If we put \( y = 1 \) in Definition 8(p), we get (h).
The condition (k) is obtained from condition (h) by applying equality (1) of Proposition 1.
If we put \( y = z \) in in Definition 8(p), we get (m).
If we put \(z = 1\) in (m), we get (n).
Definition 9. Let \(J\) be a JU-ideal of a \(A\). \(J\) is a (\(\star\))-ideal of \(A\) if
Proposition 8. Let \(J\) be a (\(\star\))-ideal of a JU-algebra \(A\). Then
Proof. The Condition (q) is obtained by putting \( y = 1 \) in Definition 9(\(\star\)). The Condition (q) can be obtained from the contraposition of Definition 9(\(\star\)).
Theorem 6. An ideal \(J\) of a JU-algebra \(A\) is a closed (\(\star\))-ideal if and only if \(\varphi(A) = \{\varphi(x) : x\in A \} \, \subseteq \, J\).
Proof.
Let \(J\) be an JU-ideal of \(A\). If \(\varphi(A) \, \subseteq \, J\), then obviously \(\varphi(J) \, \subseteq \, J\) holds, i.e., the
ideal \(J\) is closed.
Let \(x, y \in A\) be arbitrary elements. Then \(y \cdot (x \cdot y) \leqslant \varphi(x)\in J\) by Proposition 1(3) and hypothesis \(\varphi(A) \, \subseteq \, J\).
Thus \(y \cdot (x \cdot y) \in J\) by Lemma 2. Hence \(x \cdot y \in J\) by (J-2). So, \(J\) is a (\(\star\))-ideal of \(A\).
Let \( J \) be a closed (\(\star\))-ideal of \( A \). For \(x \in A\), we have \(x \in A \, \vee \, \neg(\in J)\). If \(x \in J\), then \(\varphi(x) \in J\) because \( J \) is a closed ideal of \( A \).
If \(\neg(x \in J)\), then from \(\neg(x \in J) \, \wedge \, 1 \in J\) it follows \(\varphi(x) = x \cdot 1 \in J\) because \( J \) is a (\(\star\))-ideal of \( A \).
Definition 10. Let \(J\) be a JU-ideal of a JU-algebra \(A\). \(J\) is an associative JU-ideal of \(A\) is
Theorem 7. An associative ideal \(J\) of a JU-algebra \(A\) is closed and ag-ideal of \(A\).
Proof. If we put \( x = 1 \) in Definition 10(A), we get \(\varphi(z) \cdot 1 \in J \, \Longrightarrow \, 1 \cdot z \in J\), i.e. we get \(\varphi^{2}(z) \in J \, \Longrightarrow \, z \in J\). This means that \(J\) is an ag-ideal of \(A\). If we put \( z = 1 \) in Definition 10(A), we get \(\varphi(1) \cdot x \in J \, \Longrightarrow \, x \cdot 1 \in J\), i.e. we get \(x \in J \, \Longrightarrow \, \varphi(x) \in J\). So, \(J\) is a closed JU-ideal of \(A\).